(5x-3)-4(x+2)=0

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Solution for (5x-3)-4(x+2)=0 equation:



(5x-3)-4(x+2)=0
We multiply parentheses
(5x-3)-4x-8=0
We get rid of parentheses
5x-4x-3-8=0
We add all the numbers together, and all the variables
x-11=0
We move all terms containing x to the left, all other terms to the right
x=11

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