4(2x+1)=29+2(2x-5)

Solution for 4(2x+1)=29+2(2x-5) equation:

4(2x+1)=29+2(2x-5)

We move all terms to the left:

4(2x+1)-(29+2(2x-5))=0

We multiply parentheses

8x-(29+2(2x-5))+4=0


We calculate terms in parentheses: -(29+2(2x-5)), so:

29+2(2x-5)

determiningTheFunctionDomain
2(2x-5)+29

We multiply parentheses

4x-10+29

We add all the numbers together, and all the variables

4x+19

Back to the equation:

-(4x+19)


We get rid of parentheses

8x-4x-19+4=0

We add all the numbers together, and all the variables

4x-15=0

We move all terms containing x to the left, all other terms to the right

4x=15

x=15/4

x=3+3/4