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16=5/9(f-32)
We move all terms to the left:
16-(5/9(f-32))=0
Domain of the equation: 9(f-32))!=0We multiply all the terms by the denominator
f∈R
-(5+16*9(f-32))=0
We calculate terms in parentheses: -(5+16*9(f-32)), so:
5+16*9(f-32)
determiningTheFunctionDomain 16*9(f-32)+5
Wy multiply elements
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Back to the equation:
-(144f(f+5)
We calculate terms in parentheses: -(144f(f+5), so:
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We calculate terms in parentheses: -(144f(f+5), so:
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We calculate terms in parentheses: -(144f(f+5), so:
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We calculate terms in parentheses: -(144f(f+5), so:
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We calculate terms in parentheses: -(144f(f+5), so:
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We calculate terms in parentheses: -(144f(f+5), so:
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We calculate terms in parentheses: -(144f(f+5), so:
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We calculate terms in parentheses: -(144f(f+5), so:
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We calculate terms in parentheses: -(144f(f+5), so:
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We calculate terms in parentheses: -(144f(f+5), so:
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We calculate terms in parentheses: -(144f(f+5), so:
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We calculate terms in parentheses: -(144f(f+5), so:
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We calculate terms in parentheses: -(144f(f+5), so:
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We calculate terms in parentheses: -(144f(f+5), so:
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