7+z=1/2(4z-2)

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Solution for 7+z=1/2(4z-2) equation: 



7+z=1/2(4z-2)

We move all terms to the left:

7+z-(1/2(4z-2))=0



Domain of the equation: 2(4z-2))!=0

z∈R



We multiply all the terms by the denominator


z*2(4z-2))-(1+7*2(4z-2))=0

Wy multiply elements

2z^2(4+14z(4=0

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