H=60t-5t2

Solution for H=60t-5t2 equation:

=60H-5H^2

We move all terms to the left:

-(60H-5H^2)=0

We get rid of parentheses

5H^2-60H=0

a = 5; b = -60; c = 0;
Δ = b2-4ac
Δ = -602-4·5·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-60}{2*5}=\frac{0}{10}
=0
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+60}{2*5}=\frac{120}{10}
=12
$