y+(y+12)+(y+12)+(y-12)=164

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Solution for y+(y+12)+(y+12)+(y-12)=164 equation: 



y+(y+12)+(y+12)+(y-12)=164

We move all terms to the left:

y+(y+12)+(y+12)+(y-12)-(164)=0

We get rid of parentheses

y+y+y+y+12+12-12-164=0

We add all the numbers together, and all the variables

4y-152=0

We move all terms containing y to the left, all other terms to the right

4y=152

y=152/4

y=38

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