2c-3=3(6-c)+7c

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Solution for 2c-3=3(6-c)+7c equation: 



2c-3=3(6-c)+7c

We move all terms to the left:

2c-3-(3(6-c)+7c)=0

We add all the numbers together, and all the variables

2c-(3(-1c+6)+7c)-3=0



We calculate terms in parentheses: -(3(-1c+6)+7c), so:

3(-1c+6)+7c

We add all the numbers together, and all the variables

7c+3(-1c+6)

We multiply parentheses

7c-3c+18

We add all the numbers together, and all the variables

4c+18

Back to the equation:

-(4c+18)



We get rid of parentheses

2c-4c-18-3=0

We add all the numbers together, and all the variables

-2c-21=0

We move all terms containing c to the left, all other terms to the right

-2c=21

c=21/-2

c=-10+1/2

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