F(x)=(x+1)+(x)+(x-1)

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Solution for F(x)=(x+1)+(x)+(x-1) equation: 



(F)=(F+1)+(F)+(F-1)

We move all terms to the left:

(F)-((F+1)+(F)+(F-1))=0



We calculate terms in parentheses: -((F+1)+F+(F-1)), so:

(F+1)+F+(F-1)

We add all the numbers together, and all the variables

F+(F+1)+(F-1)

We get rid of parentheses

F+F+F+1-1

We add all the numbers together, and all the variables

3F

Back to the equation:

-(3F)



We add all the numbers together, and all the variables

-2F=0

F=0/-2

F=0

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