F(x)=2(x-1)+3(x+1)

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Solution for F(x)=2(x-1)+3(x+1) equation:



(F)=2(F-1)+3(F+1)
We move all terms to the left:
(F)-(2(F-1)+3(F+1))=0
We calculate terms in parentheses: -(2(F-1)+3(F+1)), so:
2(F-1)+3(F+1)
We multiply parentheses
2F+3F-2+3
We add all the numbers together, and all the variables
5F+1
Back to the equation:
-(5F+1)
We get rid of parentheses
F-5F-1=0
We add all the numbers together, and all the variables
-4F-1=0
We move all terms containing F to the left, all other terms to the right
-4F=1
F=1/-4
F=-1/4

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