(1+R)=(1+r)12

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Solution for (1+R)=(1+r)12 equation: 



(1+)=(1+R)12

We move all terms to the left:

(1+)-((1+R)12)=0

We add all the numbers together, and all the variables

-((R+1)12)+0=0

We add all the numbers together, and all the variables

-((R+1)12)=0



We calculate terms in parentheses: -((R+1)12), so:

(R+1)12

We multiply parentheses

12R+12

Back to the equation:

-(12R+12)



We get rid of parentheses

-12R-12=0

We move all terms containing R to the left, all other terms to the right

-12R=12

R=12/-12

R=-1

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