F(7)=3(n-1)+4

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Solution for F(7)=3(n-1)+4 equation: 



(7)=3(F-1)+4

We move all terms to the left:

(7)-(3(F-1)+4)=0



We calculate terms in parentheses: -(3(F-1)+4), so:

3(F-1)+4

We multiply parentheses

3F-3+4

We add all the numbers together, and all the variables

3F+1

Back to the equation:

-(3F+1)



We get rid of parentheses

-3F-1+7=0

We add all the numbers together, and all the variables

-3F+6=0

We move all terms containing F to the left, all other terms to the right

-3F=-6

F=-6/-3

F=+2

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