53=3(3z+3)+3z

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Solution for 53=3(3z+3)+3z equation: 



53=3(3z+3)+3z

We move all terms to the left:

53-(3(3z+3)+3z)=0



We calculate terms in parentheses: -(3(3z+3)+3z), so:

3(3z+3)+3z

We add all the numbers together, and all the variables

3z+3(3z+3)

We multiply parentheses

3z+9z+9

We add all the numbers together, and all the variables

12z+9

Back to the equation:

-(12z+9)



We get rid of parentheses

-12z-9+53=0

We add all the numbers together, and all the variables

-12z+44=0

We move all terms containing z to the left, all other terms to the right

-12z=-44

z=-44/-12

z=3+2/3

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