C=(1.25x2)-5.05

Solution for C=(1.25x2)-5.05 equation:

=(1.25C^2)-5.05

We move all terms to the left:

-((1.25C^2)-5.05)=0


We calculate terms in parentheses: -((1.25C^2)-5.05), so:

(1.25C^2)-5.05

We get rid of parentheses

1.25C^2-5.05

Back to the equation:

-(1.25C^2-5.05)


We get rid of parentheses

-1.25C^2+5.05=0

a = -1.25; b = 0; c = +5.05;
Δ = b2-4ac
Δ = 02-4·(-1.25)·5.05
Δ = 25.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{25.25}}{2*-1.25}=\frac{0-\sqrt{25.25}}{-2.5}
=-\frac{\sqrt{}}{-2.5}
$
$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{25.25}}{2*-1.25}=\frac{0+\sqrt{25.25}}{-2.5}
=\frac{\sqrt{}}{-2.5}
$