3(b-4)=5

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Solution for 3(b-4)=5 equation: 



3(b-4)=5

We move all terms to the left:

3(b-4)-(5)=0

We multiply parentheses

3b-12-5=0

We add all the numbers together, and all the variables

3b-17=0

We move all terms containing b to the left, all other terms to the right

3b=17

b=17/3

b=5+2/3

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