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=1.25C^2-5.05
We move all terms to the left:
-(1.25C^2-5.05)=0
We get rid of parentheses
-1.25C^2+5.05=0
a = -1.25; b = 0; c = +5.05;
Δ = b2-4ac
Δ = 02-4·(-1.25)·5.05
Δ = 25.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{25.25}}{2*-1.25}=\frac{0-\sqrt{25.25}}{-2.5} =-\frac{\sqrt{}}{-2.5} $$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{25.25}}{2*-1.25}=\frac{0+\sqrt{25.25}}{-2.5} =\frac{\sqrt{}}{-2.5} $
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