C(h+4)=50+20h

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Solution for C(h+4)=50+20h equation: 



(C+4)=50+20C

We move all terms to the left:

(C+4)-(50+20C)=0

We add all the numbers together, and all the variables

(C+4)-(20C+50)=0

We get rid of parentheses

C-20C+4-50=0

We add all the numbers together, and all the variables

-19C-46=0

We move all terms containing C to the left, all other terms to the right

-19C=46

C=46/-19

C=-2+8/19

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