3(z+1)+7=z+6

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Solution for 3(z+1)+7=z+6 equation: 



3(z+1)+7=z+6

We move all terms to the left:

3(z+1)+7-(z+6)=0

We multiply parentheses

3z-(z+6)+3+7=0

We get rid of parentheses

3z-z-6+3+7=0

We add all the numbers together, and all the variables

2z+4=0

We move all terms containing z to the left, all other terms to the right

2z=-4

z=-4/2

z=-2

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