1/2b+3=12

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Solution for 1/2b+3=12 equation: 



1/2b+3=12

We move all terms to the left:

1/2b+3-(12)=0



Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R



We add all the numbers together, and all the variables

1/2b-9=0

We multiply all the terms by the denominator


-9*2b+1=0

Wy multiply elements

-18b+1=0

We move all terms containing b to the left, all other terms to the right

-18b=-1

b=-1/-18

b=1/18

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