B=5/4(j-25)

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Solution for B=5/4(j-25) equation: 



=5/4(B-25)

We move all terms to the left:

-(5/4(B-25))=0



Domain of the equation: 4(B-25))!=0

B∈R



We multiply all the terms by the denominator


-(5=0

We add all the numbers together, and all the variables

=0

B=0/1

B=0

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