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(3x+-8)(x-6)=0
We add all the numbers together, and all the variables
(3x-8)(x-6)=0
We multiply parentheses ..
(+3x^2-18x-8x+48)=0
We get rid of parentheses
3x^2-18x-8x+48=0
We add all the numbers together, and all the variables
3x^2-26x+48=0
a = 3; b = -26; c = +48;
Δ = b2-4ac
Δ = -262-4·3·48
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-10}{2*3}=\frac{16}{6} =2+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+10}{2*3}=\frac{36}{6} =6 $
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