4n+2=6(1/3n-2=3)

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Solution for 4n+2=6(1/3n-2=3) equation:



4n+2=6(1/3n-2=3)
We move all terms to the left:
4n+2-(6(1/3n-2)=0
Domain of the equation: 3n-2)+2!=0
n∈R
We multiply all the terms by the denominator
4n*3n-2)+2-(6(1=0
We add all the numbers together, and all the variables
4n*3n=0
Wy multiply elements
12n^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{24}=0$

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