B=(3/2)(j-27)

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Solution for B=(3/2)(j-27) equation: 



=(3/2)(B-27)

We move all terms to the left:

-((3/2)(B-27))=0



Domain of the equation: 2)(B-27))!=0

B∈R



We add all the numbers together, and all the variables

-((+3/2)(B-27))=0

We multiply parentheses ..

-((+3B^2+3/2*-27))=0

We multiply all the terms by the denominator


-((+3B^2+3=0

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