3/4x+5=1/2x+9-x

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Solution for 3/4x+5=1/2x+9-x equation:



3/4x+5=1/2x+9-x
We move all terms to the left:
3/4x+5-(1/2x+9-x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x+9-x)!=0
We move all terms containing x to the left, all other terms to the right
2x-x)!=-9
x∈R
We add all the numbers together, and all the variables
3/4x-(-1x+1/2x+9)+5=0
We get rid of parentheses
3/4x+1x-1/2x-9+5=0
We calculate fractions
1x+6x/8x^2+(-4x)/8x^2-9+5=0
We add all the numbers together, and all the variables
x+6x/8x^2+(-4x)/8x^2-4=0
We multiply all the terms by the denominator
x*8x^2+6x+(-4x)-4*8x^2=0
We add all the numbers together, and all the variables
6x+x*8x^2+(-4x)-4*8x^2=0
Wy multiply elements
8x^3-32x^2+6x+(-4x)=0
We get rid of parentheses
8x^3-32x^2+6x-4x=0
We do not support expression: x^3

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