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6v+22=8v-2(1+7v)
We move all terms to the left:
6v+22-(8v-2(1+7v))=0
We add all the numbers together, and all the variables
6v-(8v-2(7v+1))+22=0
We calculate terms in parentheses: -(8v-2(7v+1)), so:We get rid of parentheses
8v-2(7v+1)
We multiply parentheses
8v-14v-2
We add all the numbers together, and all the variables
-6v-2
Back to the equation:
-(-6v-2)
6v+6v+2+22=0
We add all the numbers together, and all the variables
12v+24=0
We move all terms containing v to the left, all other terms to the right
12v=-24
v=-24/12
v=-2
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