A=5x(3x-4X)

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Solution for A=5x(3x-4X) equation: 



=5A(3A-4A)

We move all terms to the left:

-(5A(3A-4A))=0

We add all the numbers together, and all the variables

-(5A(-1A))=0



We calculate terms in parentheses: -(5A(-1A)), so:

5A(-1A)

We multiply parentheses

-5A^2

Back to the equation:

-(-5A^2)



We get rid of parentheses

5A^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$A=\frac{-b}{2a}=\frac{0}{10}=0$

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