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(A)=A(60-2A)
We move all terms to the left:
(A)-(A(60-2A))=0
We add all the numbers together, and all the variables
A-(A(-2A+60))=0
We calculate terms in parentheses: -(A(-2A+60)), so:We get rid of parentheses
A(-2A+60)
We multiply parentheses
-2A^2+60A
Back to the equation:
-(-2A^2+60A)
2A^2-60A+A=0
We add all the numbers together, and all the variables
2A^2-59A=0
a = 2; b = -59; c = 0;
Δ = b2-4ac
Δ = -592-4·2·0
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3481}=59$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-59}{2*2}=\frac{0}{4} =0 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+59}{2*2}=\frac{118}{4} =29+1/2 $
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