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X(6-2X)=3X-1
We move all terms to the left:
X(6-2X)-(3X-1)=0
We add all the numbers together, and all the variables
X(-2X+6)-(3X-1)=0
We multiply parentheses
-2X^2+6X-(3X-1)=0
We get rid of parentheses
-2X^2+6X-3X+1=0
We add all the numbers together, and all the variables
-2X^2+3X+1=0
a = -2; b = 3; c = +1;
Δ = b2-4ac
Δ = 32-4·(-2)·1
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{17}}{2*-2}=\frac{-3-\sqrt{17}}{-4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{17}}{2*-2}=\frac{-3+\sqrt{17}}{-4} $
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