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c=1/2(c-4)-(5+c)
We move all terms to the left:
c-(1/2(c-4)-(5+c))=0
Domain of the equation: 2(c-4)-(5+c))!=0We add all the numbers together, and all the variables
c∈R
c-(1/2(c-4)-(c+5))=0
We multiply all the terms by the denominator
c*2(c-4)-(c+5))-(1=0
Wy multiply elements
2c^2(c-(c+5))-(1=0
We add all the numbers together, and all the variables
2c^2(c-(c+5))=0
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