A(n)=5+2(n-1)

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Solution for A(n)=5+2(n-1) equation: 



(A)=5+2(A-1)

We move all terms to the left:

(A)-(5+2(A-1))=0



We calculate terms in parentheses: -(5+2(A-1)), so:

5+2(A-1)

determiningTheFunctionDomain
2(A-1)+5

We multiply parentheses

2A-2+5

We add all the numbers together, and all the variables

2A+3

Back to the equation:

-(2A+3)



We get rid of parentheses

A-2A-3=0

We add all the numbers together, and all the variables

-1A-3=0

We move all terms containing A to the left, all other terms to the right

-A=3

A=3/-1

A=-3

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