(6t-4)/(3t+2)=-7/2

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Solution for (6t-4)/(3t+2)=-7/2 equation: 



(6t-4)/(3t+2)=-7/2

We move all terms to the left:

(6t-4)/(3t+2)-(-7/2)=0



Domain of the equation: (3t+2)!=0

We move all terms containing t to the left, all other terms to the right

3t!=-2

t!=-2/3

t!=-2/3

t∈R



We get rid of parentheses

(6t-4)/(3t+2)+7/2=0

We calculate fractions


(12t-8)/(6t+4)+(21t+14)/(6t+4)=0

We multiply all the terms by the denominator


(12t-8)+(21t+14)=0

We get rid of parentheses

12t+21t-8+14=0

We add all the numbers together, and all the variables

33t+6=0

We move all terms containing t to the left, all other terms to the right

33t=-6

t=-6/33

t=-2/11

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