1/3(4(6-5p)-7(3p+2))=17

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Solution for 1/3(4(6-5p)-7(3p+2))=17 equation: 



1/3(4(6-5p)-7(3p+2))=17

We move all terms to the left:

1/3(4(6-5p)-7(3p+2))-(17)=0



Domain of the equation: 3(4(6-5p)-7(3p+2))!=0

p∈R



We add all the numbers together, and all the variables

1/3(4(-5p+6)-7(3p+2))-17=0

We multiply all the terms by the denominator


-17*3(4(-5p+6)-7(3p+2))+1=0

Wy multiply elements

-51p(4+1=0

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