If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9x=3x(3x-7)
We move all terms to the left:
9x-(3x(3x-7))=0
We calculate terms in parentheses: -(3x(3x-7)), so:We get rid of parentheses
3x(3x-7)
We multiply parentheses
9x^2-21x
Back to the equation:
-(9x^2-21x)
-9x^2+9x+21x=0
We add all the numbers together, and all the variables
-9x^2+30x=0
a = -9; b = 30; c = 0;
Δ = b2-4ac
Δ = 302-4·(-9)·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30}{2*-9}=\frac{-60}{-18} =3+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30}{2*-9}=\frac{0}{-18} =0 $
| 2x+4x+108=108 | | 12x-5=-25 | | 7x+54=10 | | 18x-5=-2x+1 | | 4z/9+3=-7 | | x^2–11x–102=0. | | x²–11x–102=0. | | -4x+2x=30-20 | | -4x+2x=39-20 | | X-9=3+(2*x) | | 2(x-2)=54 | | 9=11-(r-5) | | 22x-400-x^2=0 | | 2x–3=5x–6 | | n-6.0=8 | | 11x+10=10×+6 | | x-0.4=3.25 | | 450=1.5x^2+68x | | x^2+√6x-3=0 | | x-(x^2+9x+20)+3=0 | | 52n+1/25=(5)3 | | (x-3)2-4(x-5)=(4-x)2 | | -2,-4w=7w-8 | | 2c+7=-21 | | 3+v=2(v-1) | | (5x+12)=(x+6) | | 2(6m+3)=m-7 | | 22p+3=4p+12= | | 4a+7=2a+1 | | Q/5+9/5+8q=11-q | | -9x-7=65 | | 8n+2=6n+2 |