2(6m+3)=m-7

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Solution for 2(6m+3)=m-7 equation: 



2(6m+3)=m-7

We move all terms to the left:

2(6m+3)-(m-7)=0

We multiply parentheses

12m-(m-7)+6=0

We get rid of parentheses

12m-m+7+6=0

We add all the numbers together, and all the variables

11m+13=0

We move all terms containing m to the left, all other terms to the right

11m=-13

m=-13/11

m=-1+2/11

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