(x-3)2-4(x-5)=(4-x)2

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Solution for (x-3)2-4(x-5)=(4-x)2 equation: 



(x-3)2-4(x-5)=(4-x)2

We move all terms to the left:

(x-3)2-4(x-5)-((4-x)2)=0

We add all the numbers together, and all the variables

(x-3)2-4(x-5)-((-1x+4)2)=0

We multiply parentheses

2x-4x-((-1x+4)2)-6+20=0



We calculate terms in parentheses: -((-1x+4)2), so:

(-1x+4)2

We multiply parentheses

-2x+8

Back to the equation:

-(-2x+8)



We add all the numbers together, and all the variables

-2x-(-2x+8)+14=0

We get rid of parentheses

-2x+2x-8+14=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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