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9x^2-29x-28=0
a = 9; b = -29; c = -28;
Δ = b2-4ac
Δ = -292-4·9·(-28)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-43}{2*9}=\frac{-14}{18} =-7/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+43}{2*9}=\frac{72}{18} =4 $
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