2/31)+7(p-12)=-2(2p-

Solution for 2/31)+7(p-12)=-2(2p- equation:

2/31)+7(p-12)=-2(2p-

We move all terms to the left:

2/31)+7(p-12)-(-2(2p-)=0


Domain of the equation: 31)+7(p!=0

p∈R


We add all the numbers together, and all the variables

2/31)+7(p-2(+2p)-12)-(=0

We add all the numbers together, and all the variables

2/31)+7(p-2(+2p)=0

We multiply parentheses

2/31)+7(p-4p=0

We multiply all the terms by the denominator


-4p*31)+7(p+2=0

Wy multiply elements

-124p^2+2=0

a = -124; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-124)·2
Δ = 992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{992}=\sqrt{16*62}=\sqrt{16}*\sqrt{62}=4\sqrt{62}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{62}}{2*-124}=\frac{0-4\sqrt{62}}{-248}
=-\frac{4\sqrt{62}}{-248}
=-\frac{\sqrt{62}}{-62}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{62}}{2*-124}=\frac{0+4\sqrt{62}}{-248}
=\frac{4\sqrt{62}}{-248}
=\frac{\sqrt{62}}{-62}
$