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2/3p-8=-4p+2+7
We move all terms to the left:
2/3p-8-(-4p+2+7)=0
Domain of the equation: 3p!=0We add all the numbers together, and all the variables
p!=0/3
p!=0
p∈R
2/3p-(-4p+9)-8=0
We get rid of parentheses
2/3p+4p-9-8=0
We multiply all the terms by the denominator
4p*3p-9*3p-8*3p+2=0
Wy multiply elements
12p^2-27p-24p+2=0
We add all the numbers together, and all the variables
12p^2-51p+2=0
a = 12; b = -51; c = +2;
Δ = b2-4ac
Δ = -512-4·12·2
Δ = 2505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-\sqrt{2505}}{2*12}=\frac{51-\sqrt{2505}}{24} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+\sqrt{2505}}{2*12}=\frac{51+\sqrt{2505}}{24} $
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