9x2+117x-1024=0

Solution for 9x2+117x-1024=0 equation:

9x^2+117x-1024=0

a = 9; b = 117; c = -1024;
Δ = b2-4ac
Δ = 1172-4·9·(-1024)
Δ = 50553
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{50553}=\sqrt{9*5617}=\sqrt{9}*\sqrt{5617}=3\sqrt{5617}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(117)-3\sqrt{5617}}{2*9}=\frac{-117-3\sqrt{5617}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(117)+3\sqrt{5617}}{2*9}=\frac{-117+3\sqrt{5617}}{18}
$