1/2f-2/5+3/5f=1/5

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Solution for 1/2f-2/5+3/5f=1/5 equation:



1/2f-2/5+3/5f=1/5
We move all terms to the left:
1/2f-2/5+3/5f-(1/5)=0
Domain of the equation: 2f!=0
f!=0/2
f!=0
f∈R
Domain of the equation: 5f!=0
f!=0/5
f!=0
f∈R
We add all the numbers together, and all the variables
1/2f+3/5f-2/5-(+1/5)=0
We get rid of parentheses
1/2f+3/5f-2/5-1/5=0
We calculate fractions
125f/250f^2+6f/250f^2+(-2f-2)/250f^2=0
We multiply all the terms by the denominator
125f+6f+(-2f-2)=0
We add all the numbers together, and all the variables
131f+(-2f-2)=0
We get rid of parentheses
131f-2f-2=0
We add all the numbers together, and all the variables
129f-2=0
We move all terms containing f to the left, all other terms to the right
129f=2
f=2/129
f=2/129

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