-4(y-3y)+6=-2(2y-y)+8+9y

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Solution for -4(y-3y)+6=-2(2y-y)+8+9y equation: 



-4(y-3y)+6=-2(2y-y)+8+9y

We move all terms to the left:

-4(y-3y)+6-(-2(2y-y)+8+9y)=0

We add all the numbers together, and all the variables

-4(-2y)-(-2(+y)+8+9y)+6=0

We multiply parentheses

8y-(-2(+y)+8+9y)+6=0



We calculate terms in parentheses: -(-2(+y)+8+9y), so:

-2(+y)+8+9y

determiningTheFunctionDomain
-2(+y)+9y+8

We add all the numbers together, and all the variables

9y-2(+y)+8

We multiply parentheses

9y-2y+8

We add all the numbers together, and all the variables

7y+8

Back to the equation:

-(7y+8)



We get rid of parentheses

8y-7y-8+6=0

We add all the numbers together, and all the variables

y-2=0

We move all terms containing y to the left, all other terms to the right

y=2

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