9x-10-2x=3(-20+3x)

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Solution for 9x-10-2x=3(-20+3x) equation: 



9x-10-2x=3(-20+3x)

We move all terms to the left:

9x-10-2x-(3(-20+3x))=0

We add all the numbers together, and all the variables

9x-2x-(3(3x-20))-10=0

We add all the numbers together, and all the variables

7x-(3(3x-20))-10=0



We calculate terms in parentheses: -(3(3x-20)), so:

3(3x-20)

We multiply parentheses

9x-60

Back to the equation:

-(9x-60)



We get rid of parentheses

7x-9x+60-10=0

We add all the numbers together, and all the variables

-2x+50=0

We move all terms containing x to the left, all other terms to the right

-2x=-50

x=-50/-2

x=+25

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