2-8(2x-6)=-7(2x+4)+10

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Solution for 2-8(2x-6)=-7(2x+4)+10 equation: 



2-8(2x-6)=-7(2x+4)+10

We move all terms to the left:

2-8(2x-6)-(-7(2x+4)+10)=0

We multiply parentheses

-16x-(-7(2x+4)+10)+48+2=0



We calculate terms in parentheses: -(-7(2x+4)+10), so:

-7(2x+4)+10

We multiply parentheses

-14x-28+10

We add all the numbers together, and all the variables

-14x-18

Back to the equation:

-(-14x-18)



We add all the numbers together, and all the variables

-16x-(-14x-18)+50=0

We get rid of parentheses

-16x+14x+18+50=0

We add all the numbers together, and all the variables

-2x+68=0

We move all terms containing x to the left, all other terms to the right

-2x=-68

x=-68/-2

x=+34

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