4/5x+3/20x=38

Solution for 4/5x+3/20x=38 equation:

4/5x+3/20x=38

We move all terms to the left:

4/5x+3/20x-(38)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 20x!=0

x!=0/20

x!=0

x∈R


We calculate fractions


80x/100x^2+15x/100x^2-38=0

We multiply all the terms by the denominator


80x+15x-38*100x^2=0

We add all the numbers together, and all the variables

95x-38*100x^2=0

Wy multiply elements

-3800x^2+95x=0

a = -3800; b = 95; c = 0;
Δ = b2-4ac
Δ = 952-4·(-3800)·0
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9025}=95$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(95)-95}{2*-3800}=\frac{-190}{-7600}
=1/40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(95)+95}{2*-3800}=\frac{0}{-7600}
=0
$