9n-1=7(n+2)+7n

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Solution for 9n-1=7(n+2)+7n equation: 



9n-1=7(n+2)+7n

We move all terms to the left:

9n-1-(7(n+2)+7n)=0



We calculate terms in parentheses: -(7(n+2)+7n), so:

7(n+2)+7n

We add all the numbers together, and all the variables

7n+7(n+2)

We multiply parentheses

7n+7n+14

We add all the numbers together, and all the variables

14n+14

Back to the equation:

-(14n+14)



We get rid of parentheses

9n-14n-14-1=0

We add all the numbers together, and all the variables

-5n-15=0

We move all terms containing n to the left, all other terms to the right

-5n=15

n=15/-5

n=-3

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