1-y=(3y-19)/5

Solution for 1-y=(3y-19)/5 equation:

1-y=(3y-19)/5

We move all terms to the left:

1-y-((3y-19)/5)=0

We add all the numbers together, and all the variables

-1y-((3y-19)/5)+1=0

We multiply all the terms by the denominator


-1y*5)-((3y-19)+1*5)=0

We add all the numbers together, and all the variables

-1y*5)-((3y-19)=0

Wy multiply elements

-5y^2=0

a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{-10}=0$