0=5r(r+2r)

Solution for 0=5r(r+2r) equation:

0=5r(r+2r)

We move all terms to the left:

0-(5r(r+2r))=0

We add all the numbers together, and all the variables

-(5r(+3r))+0=0

We add all the numbers together, and all the variables

-(5r(+3r))=0


We calculate terms in parentheses: -(5r(+3r)), so:

5r(+3r)

We multiply parentheses

15r^2

Back to the equation:

-(15r^2)


a = -15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-15)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{-30}=0$