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9=12x-4x^2
We move all terms to the left:
9-(12x-4x^2)=0
We get rid of parentheses
4x^2-12x+9=0
a = 4; b = -12; c = +9;
Δ = b2-4ac
Δ = -122-4·4·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{12}{8}=1+1/2$
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