(50+2x)(34+2x)=2240

Solution for (50+2x)(34+2x)=2240 equation:

(50+2x)(34+2x)=2240

We move all terms to the left:

(50+2x)(34+2x)-(2240)=0

We add all the numbers together, and all the variables

(2x+50)(2x+34)-2240=0

We multiply parentheses ..

(+4x^2+68x+100x+1700)-2240=0

We get rid of parentheses

4x^2+68x+100x+1700-2240=0

We add all the numbers together, and all the variables

4x^2+168x-540=0

a = 4; b = 168; c = -540;
Δ = b2-4ac
Δ = 1682-4·4·(-540)
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36864}=192$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(168)-192}{2*4}=\frac{-360}{8}
=-45
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(168)+192}{2*4}=\frac{24}{8}
=3
$