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80-x=1/3x
We move all terms to the left:
80-x-(1/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-x-(+1/3x)+80=0
We add all the numbers together, and all the variables
-1x-(+1/3x)+80=0
We get rid of parentheses
-1x-1/3x+80=0
We multiply all the terms by the denominator
-1x*3x+80*3x-1=0
Wy multiply elements
-3x^2+240x-1=0
a = -3; b = 240; c = -1;
Δ = b2-4ac
Δ = 2402-4·(-3)·(-1)
Δ = 57588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{57588}=\sqrt{4*14397}=\sqrt{4}*\sqrt{14397}=2\sqrt{14397}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-2\sqrt{14397}}{2*-3}=\frac{-240-2\sqrt{14397}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+2\sqrt{14397}}{2*-3}=\frac{-240+2\sqrt{14397}}{-6} $
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