2(2t+4)=48

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Solution for 2(2t+4)=48 equation: 



2(2t+4)=48

We move all terms to the left:

2(2t+4)-(48)=0

We multiply parentheses

4t+8-48=0

We add all the numbers together, and all the variables

4t-40=0

We move all terms containing t to the left, all other terms to the right

4t=40

t=40/4

t=10

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